What did you do to become confident of your ability to do these things? Be specific. Reflect on the study skills you used so that you can continue to use them. Congratulations! You have achieved the objectives in this section. Ⓐ After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.Ĭhoose how would you respond to the statement “I can solve quadratic equations of the form a times the square of x minus h equals k using the Square Root Property.” “Confidently,” “with some help,” or “No, I don’t get it.” In your own words, explain how to use the Square Root Property to solve the quadratic equation ( x + 2 ) 2 = 16 ( x + 2 ) 2 = 16. We earlier defined the square root of a number in this way: So, every positive number has two square roots-one positive and one negative. Therefore, both 13 and −13 are square roots of 169. Previously we learned that since 169 is the square of 13, we can also say that 13 is a square root of 169. īut what happens when we have an equation like x 2 = 7? Since 7 is not a perfect square, we cannot solve the equation by factoring. In each case, we would get two solutions, x = 4, x = −4 x = 4, x = −4 and x = 5, x = −5. We can easily use factoring to find the solutions of similar equations, like x 2 = 16 and x 2 = 25, because 16 and 25 are perfect squares. Now we have to divide the two factors +6 and +9 by the coefficient of x 2, that is 2.( x − 3 ) ( x + 3 ) = 0 ( x − 3 ) ( x + 3 ) = 0 So, m ultiply the coefficient of x 2 and the constant term "+27".ĭecompose +54 into two factors such that the product of two factors is equal to +54 and the addition of two factors is equal to the coefficient of x, that is +15. In the given quadratic equation, the coefficient of x 2 is not 1. In the given quadratic equation, the coefficient of x 2 is 1.ĭecompose the constant term +14 into two factors such that the product of the two factors is equal to +14 and the addition of two factors is equal to the coefficient of x, that is +9.įactor the given quadratic equation using +2 and +7 and solve for x.ĭecompose the constant term +14 into two factors such that the product of the two factors is equal to +14 and the addition of two factors is equal to the coefficient of x, that is -9.įactor the given quadratic equation using -2 and -7 and solve for x.ĭecompose the constant term -15 into two factors such that the product of the two factors is equal to -15 and the addition of two factors is equal to the coefficient of x, that is +2.įactor the given quadratic equation using +5 and -3 and solve for x.ĭecompose the constant term -15 into two factors such that the product of the two factors is equal to -15 and the addition of two factors is equal to the coefficient of x, that is -2.įactor the given quadratic equation using +3 and -5 and solve for x. (iv) Write the remaining number along with x (This is explained in the following example). (iii) Divide the two factors by the coefficient of x 2 and simplify as much as possible. (ii) The product of the two factors must be equal to "ac" and the addition of two factors must be equal to the coefficient of x, that is "b". (i) In a quadratic equation in the form ax 2 + bx + c = 0, if the leading coefficient is not 1, we have to multiply the coefficient of x 2 and the constant term. Solving Quadratic Equations by Factoring when Leading Coefficient is not 1 - Procedure Positive sign for smaller factor and negative sign for larger factor.
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